3.128 \(\int \frac {(a+b x)^5 (A+B x)}{x^4} \, dx\)

Optimal. Leaf size=108 \[ -\frac {a^5 A}{3 x^3}-\frac {a^4 (a B+5 A b)}{2 x^2}-\frac {5 a^3 b (a B+2 A b)}{x}+10 a^2 b^2 \log (x) (a B+A b)+\frac {1}{2} b^4 x^2 (5 a B+A b)+5 a b^3 x (2 a B+A b)+\frac {1}{3} b^5 B x^3 \]

[Out]

-1/3*a^5*A/x^3-1/2*a^4*(5*A*b+B*a)/x^2-5*a^3*b*(2*A*b+B*a)/x+5*a*b^3*(A*b+2*B*a)*x+1/2*b^4*(A*b+5*B*a)*x^2+1/3
*b^5*B*x^3+10*a^2*b^2*(A*b+B*a)*ln(x)

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Rubi [A]  time = 0.06, antiderivative size = 108, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {76} \[ 10 a^2 b^2 \log (x) (a B+A b)-\frac {a^4 (a B+5 A b)}{2 x^2}-\frac {5 a^3 b (a B+2 A b)}{x}-\frac {a^5 A}{3 x^3}+\frac {1}{2} b^4 x^2 (5 a B+A b)+5 a b^3 x (2 a B+A b)+\frac {1}{3} b^5 B x^3 \]

Antiderivative was successfully verified.

[In]

Int[((a + b*x)^5*(A + B*x))/x^4,x]

[Out]

-(a^5*A)/(3*x^3) - (a^4*(5*A*b + a*B))/(2*x^2) - (5*a^3*b*(2*A*b + a*B))/x + 5*a*b^3*(A*b + 2*a*B)*x + (b^4*(A
*b + 5*a*B)*x^2)/2 + (b^5*B*x^3)/3 + 10*a^2*b^2*(A*b + a*B)*Log[x]

Rule 76

Int[((d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_))*((e_) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*
x)*(d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, d, e, f, n}, x] && IGtQ[p, 0] && (NeQ[n, -1] || EqQ[p, 1]) && N
eQ[b*e + a*f, 0] && ( !IntegerQ[n] || LtQ[9*p + 5*n, 0] || GeQ[n + p + 1, 0] || (GeQ[n + p + 2, 0] && Rational
Q[a, b, d, e, f])) && (NeQ[n + p + 3, 0] || EqQ[p, 1])

Rubi steps

\begin {align*} \int \frac {(a+b x)^5 (A+B x)}{x^4} \, dx &=\int \left (5 a b^3 (A b+2 a B)+\frac {a^5 A}{x^4}+\frac {a^4 (5 A b+a B)}{x^3}+\frac {5 a^3 b (2 A b+a B)}{x^2}+\frac {10 a^2 b^2 (A b+a B)}{x}+b^4 (A b+5 a B) x+b^5 B x^2\right ) \, dx\\ &=-\frac {a^5 A}{3 x^3}-\frac {a^4 (5 A b+a B)}{2 x^2}-\frac {5 a^3 b (2 A b+a B)}{x}+5 a b^3 (A b+2 a B) x+\frac {1}{2} b^4 (A b+5 a B) x^2+\frac {1}{3} b^5 B x^3+10 a^2 b^2 (A b+a B) \log (x)\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 109, normalized size = 1.01 \[ \frac {-\left (a^5 (2 A+3 B x)\right )-15 a^4 b x (A+2 B x)-60 a^3 A b^2 x^2+60 a^2 b^2 x^3 \log (x) (a B+A b)+60 a^2 b^3 B x^4+15 a b^4 x^4 (2 A+B x)+b^5 x^5 (3 A+2 B x)}{6 x^3} \]

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x)^5*(A + B*x))/x^4,x]

[Out]

(-60*a^3*A*b^2*x^2 + 60*a^2*b^3*B*x^4 + 15*a*b^4*x^4*(2*A + B*x) - 15*a^4*b*x*(A + 2*B*x) + b^5*x^5*(3*A + 2*B
*x) - a^5*(2*A + 3*B*x) + 60*a^2*b^2*(A*b + a*B)*x^3*Log[x])/(6*x^3)

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fricas [A]  time = 0.90, size = 121, normalized size = 1.12 \[ \frac {2 \, B b^{5} x^{6} - 2 \, A a^{5} + 3 \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{5} + 30 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{4} + 60 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{3} \log \relax (x) - 30 \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{2} - 3 \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x}{6 \, x^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5*(B*x+A)/x^4,x, algorithm="fricas")

[Out]

1/6*(2*B*b^5*x^6 - 2*A*a^5 + 3*(5*B*a*b^4 + A*b^5)*x^5 + 30*(2*B*a^2*b^3 + A*a*b^4)*x^4 + 60*(B*a^3*b^2 + A*a^
2*b^3)*x^3*log(x) - 30*(B*a^4*b + 2*A*a^3*b^2)*x^2 - 3*(B*a^5 + 5*A*a^4*b)*x)/x^3

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giac [A]  time = 1.22, size = 118, normalized size = 1.09 \[ \frac {1}{3} \, B b^{5} x^{3} + \frac {5}{2} \, B a b^{4} x^{2} + \frac {1}{2} \, A b^{5} x^{2} + 10 \, B a^{2} b^{3} x + 5 \, A a b^{4} x + 10 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} \log \left ({\left | x \right |}\right ) - \frac {2 \, A a^{5} + 30 \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{2} + 3 \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x}{6 \, x^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5*(B*x+A)/x^4,x, algorithm="giac")

[Out]

1/3*B*b^5*x^3 + 5/2*B*a*b^4*x^2 + 1/2*A*b^5*x^2 + 10*B*a^2*b^3*x + 5*A*a*b^4*x + 10*(B*a^3*b^2 + A*a^2*b^3)*lo
g(abs(x)) - 1/6*(2*A*a^5 + 30*(B*a^4*b + 2*A*a^3*b^2)*x^2 + 3*(B*a^5 + 5*A*a^4*b)*x)/x^3

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maple [A]  time = 0.01, size = 120, normalized size = 1.11 \[ \frac {B \,b^{5} x^{3}}{3}+\frac {A \,b^{5} x^{2}}{2}+\frac {5 B a \,b^{4} x^{2}}{2}+10 A \,a^{2} b^{3} \ln \relax (x )+5 A a \,b^{4} x +10 B \,a^{3} b^{2} \ln \relax (x )+10 B \,a^{2} b^{3} x -\frac {10 A \,a^{3} b^{2}}{x}-\frac {5 B \,a^{4} b}{x}-\frac {5 A \,a^{4} b}{2 x^{2}}-\frac {B \,a^{5}}{2 x^{2}}-\frac {A \,a^{5}}{3 x^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^5*(B*x+A)/x^4,x)

[Out]

1/3*b^5*B*x^3+1/2*A*x^2*b^5+5/2*B*x^2*a*b^4+5*a*b^4*A*x+10*a^2*b^3*B*x-10*a^3*b^2/x*A-5*a^4*b/x*B+10*A*ln(x)*a
^2*b^3+10*B*ln(x)*a^3*b^2-5/2*a^4/x^2*A*b-1/2*a^5/x^2*B-1/3*a^5*A/x^3

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maxima [A]  time = 1.18, size = 117, normalized size = 1.08 \[ \frac {1}{3} \, B b^{5} x^{3} + \frac {1}{2} \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{2} + 5 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x + 10 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} \log \relax (x) - \frac {2 \, A a^{5} + 30 \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{2} + 3 \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x}{6 \, x^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5*(B*x+A)/x^4,x, algorithm="maxima")

[Out]

1/3*B*b^5*x^3 + 1/2*(5*B*a*b^4 + A*b^5)*x^2 + 5*(2*B*a^2*b^3 + A*a*b^4)*x + 10*(B*a^3*b^2 + A*a^2*b^3)*log(x)
- 1/6*(2*A*a^5 + 30*(B*a^4*b + 2*A*a^3*b^2)*x^2 + 3*(B*a^5 + 5*A*a^4*b)*x)/x^3

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mupad [B]  time = 0.06, size = 114, normalized size = 1.06 \[ x^2\,\left (\frac {A\,b^5}{2}+\frac {5\,B\,a\,b^4}{2}\right )-\frac {x\,\left (\frac {B\,a^5}{2}+\frac {5\,A\,b\,a^4}{2}\right )+\frac {A\,a^5}{3}+x^2\,\left (5\,B\,a^4\,b+10\,A\,a^3\,b^2\right )}{x^3}+\ln \relax (x)\,\left (10\,B\,a^3\,b^2+10\,A\,a^2\,b^3\right )+\frac {B\,b^5\,x^3}{3}+5\,a\,b^3\,x\,\left (A\,b+2\,B\,a\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((A + B*x)*(a + b*x)^5)/x^4,x)

[Out]

x^2*((A*b^5)/2 + (5*B*a*b^4)/2) - (x*((B*a^5)/2 + (5*A*a^4*b)/2) + (A*a^5)/3 + x^2*(10*A*a^3*b^2 + 5*B*a^4*b))
/x^3 + log(x)*(10*A*a^2*b^3 + 10*B*a^3*b^2) + (B*b^5*x^3)/3 + 5*a*b^3*x*(A*b + 2*B*a)

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sympy [A]  time = 1.16, size = 122, normalized size = 1.13 \[ \frac {B b^{5} x^{3}}{3} + 10 a^{2} b^{2} \left (A b + B a\right ) \log {\relax (x )} + x^{2} \left (\frac {A b^{5}}{2} + \frac {5 B a b^{4}}{2}\right ) + x \left (5 A a b^{4} + 10 B a^{2} b^{3}\right ) + \frac {- 2 A a^{5} + x^{2} \left (- 60 A a^{3} b^{2} - 30 B a^{4} b\right ) + x \left (- 15 A a^{4} b - 3 B a^{5}\right )}{6 x^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**5*(B*x+A)/x**4,x)

[Out]

B*b**5*x**3/3 + 10*a**2*b**2*(A*b + B*a)*log(x) + x**2*(A*b**5/2 + 5*B*a*b**4/2) + x*(5*A*a*b**4 + 10*B*a**2*b
**3) + (-2*A*a**5 + x**2*(-60*A*a**3*b**2 - 30*B*a**4*b) + x*(-15*A*a**4*b - 3*B*a**5))/(6*x**3)

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